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A proton and $α$ an particle are moving simultaneously such that the wavelength associated with them are equal. The ratio their velocities is

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1:1

2:1

1:4

4:1

answer is D.

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Detailed Solution

$λ_{1} = λ_{2} = \frac{h}{m_{1} v_{1}} = \frac{h}{m_{2} v_{2}}$
$\frac{v_{1}}{v_{2}} = \frac{m_{2}}{m_{1}} = \frac{4}{1}$

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