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Q.

A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10T . What would be the radius (in cm) of the circle described by an α  -particle moving with the same speed in the same magnetic field?

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answer is 2.

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Detailed Solution

r=mvqB0.01=mve0.1 ……(1)r'=4m×v2e×0.1 ……(2) (2)÷(1)⇒r'0.01=4mve×0.12e×0.1×mv=42=2⇒r'=0.02m=2cm.

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