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Q.

A proton has a mass of $1.67 \times 10^{- 27}$ kg and charge $1.6 \times 10^{- 19}$ coulomb. If the proton is to be accelerated through a potential difference of one million volts, then the KE is

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a

$1.6 \times 10^{- 15} J$

b

$3.2 \times 10^{- 13} J$

c

$1.6 \times 10^{- 25} J$

d

$1.6 \times 10^{- 13} J$

answer is B.

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Detailed Solution

KE = Vq = $10^{6} \times 1.6 \times 10^{- 19} = 1.6 \times 10^{- 13} J$

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A proton has a mass of 1.67×10−27 kg and charge 1.6×10−19 coulomb. If the proton is to be accelerated through a potential difference of one million volts, then the KE is