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A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be :

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1840 keV

1/1840 keV

1 keV

920 keV

answer is C.

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Detailed Solution

We know that :

Kinetic energy = Relative charge × accelerating potential

KE =1 e ×1 kV

KE =1 k eV

The kinetic energy of electron and proton will be the same as they are having same magnitude of charge and potential difference.

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