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Q.

A proton is projected with a velocity 10⁷ m/s at right angles to a uniform magnetic field of induction 100 mT. The time taken by proton to traverse 90° arc is :

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a

1.62 x 10^-7S

b

2.43 x 10^-7S

c

3.24 x 10^-7S

d

0.81x 10^-7S

answer is B.

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Detailed Solution

$T = \frac{2 πm}{qB} = 6.28 \times 10^{- 7} s for traversing 90^{0} arc time taken is T / 4 = 1.6 \times 10^{- 7} s$

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