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Q.

A proton is released from rest 10cm from a charged sheet carrying charge density of $- 2.21 \times 10^{- 9} C / m^{2}$ . it will strike the sheet after the time

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a

$4 μ s$

b

$4 \sqrt{2} μ s$

c

$2 \sqrt{2} μ s$

d

$2 μ s$

answer is A.

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Detailed Solution

$a = \frac{E q}{m} = \frac{\frac{σ}{2 ε_{0}} q}{m} S = \frac{1}{2} a t^{2} t = 4 \times 10^{- 6} s$

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