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Q.

  A proton of kinetic energy 200 MeV moving towards east enters the magnetic field of 5 T. . If direction of field is from south to north and motion is upward, the force acting on it will be (mass of proton is 1.672×1027kg)

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a

zero

b

1.6×1010 N

c

3.2×108 N

d

1.6×106 N

answer is B.

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Detailed Solution

F=qvB
But 12mv2=Kv=2Km
F=q2KmB=1.6×10192×200×1.6×10131.67×1027×51.6×1019×2×108×5N=1.6×1010N

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  A proton of kinetic energy 200 MeV moving towards east enters the magnetic field of 5 T. . If direction of field is from south to north and motion is upward, the force acting on it will be (mass of proton is 1.672×10−27kg)