A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is $3 \times 10^{8} m s^{- 1}$ . The final momentum of the object is

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$0.3 \times 10^{- 17} k g - m s^{- 1}$

$9.0 \times 10^{- 17} k g - m s^{- 1}$

$1.0 \times 10^{- 17} k g - m s^{- 1}$

$3.0 \times 10^{- 17} k g - m s^{- 1}$

answer is B.

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Detailed Solution

$\frac{P o w e r \times t i m e}{C} = m o m e n t u m m o m e n t u m = \frac{3 \times 10^{- 2} \times 10^{- 7}}{3 \times 10^{8}} m o m e n t u m = 10^{- 17}$

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