A pulse of light of duration 100ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light in $3 \times 10^{8} m s^{- 1} .$ The final momentum of the object is

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$9.0 \times 10^{- 17} k g m s^{- 1}$

$1.0 \times 10^{- 17} k g m s^{- 1}$

$0.3 \times 10^{- 17} k g m s^{- 1}$

$3.0 \times 10^{- 17} k g m s^{- 1}$

answer is C.

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Detailed Solution

Final momentum, $P = \frac{E}{c} = \frac{P \times t}{c} = \frac{30 \times 10^{- 3} \times 100 \times 10^{- 9}}{3 \times 10^{8}} = 1.0 \times 10^{- 17} k g m s^{- 1}$

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