A pump is required to lift 600kg of water per minute from a well 25m deep and to eject it with a speed of 50m/s calculate the power required to perform the above test ?

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Detailed Solution

Power of the pump
$\begin{array}{l} \frac{P = mgh + \frac{1}{2} {mv}^{2}}{t} \\ = \frac{600 \times 9 .8 \times 25 + \frac{1}{2} \times 600 \times 50 \times 50}{60} \\ = \frac{600 \times 9 .8 \times 25 + \frac{1}{2} \times 600 \times 2500}{60} \\ = 14950 W = 14 .95 KW (or) = 15 kW \end{array}$

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