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A pump of 200 W power is lifting 2kg water per second from an average depth of 10m. The velocity with which water comes out of the pump is (g = 9.8 ms^–2)

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2 ms^–1

2.5 ms^–1

4 ms^–1

3 ms^–1

answer is A.

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Detailed Solution

$P = \frac{mgh + \frac{1}{2} {mv}^{2}}{t}$

$200 = \frac{2 \times 9.8 \times 10 + \frac{1}{2} \times 2 \times v^{2}}{1}$

$\Rightarrow v = 2 {ms}^{- 1}$

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