A pure semiconductor has equal electron and hole concentration of 1016 m-3. Doping by Indium increases nh to 4.5×1022m-3. What ts ne in the doped semiconductor?

nenh=n2or ne=n2nh=1016×10164.5×1022m-3

A pure semiconductor has equal electron and hole concentration of 1016 m-3. Doping by Indium increases nh to 4.5×1022m-3. What ts ne in the doped semiconductor?

nenh=n2or ne=n2nh=1016×10164.5×1022m-3

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A pure semiconductor has equal electron and hole concentration of 10¹⁶ m^-3. Doping by Indium increases n_h to $4.5 \times 10^{22} m^{- 3}$ . What ts n_ein the doped semiconductor?

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$10^{6} m^{- 3}$

$10^{22} m^{- 3}$

$\frac{10^{32}}{4.5 \times 10^{22}} m^{- 3}$

$4 \times 10^{22} m^{- 3}$

answer is C.

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Detailed Solution

$n_{e} n_{h} = n^{2}$

$o r n_{e} = \frac{n^{2}}{n_{h}} = \frac{10^{16} \times 10^{16}}{4.5 \times 10^{22}} m^{- 3}$

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A pure semiconductor has equal electron and hole concentration of 1016 m-3. Doping by Indium increases nh to 4.5×1022m-3. What ts ne in the doped semiconductor?

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A pure semiconductor has equal electron and hole concentration of 10¹⁶ m^-3. Doping by Indium increases n_h to $4.5 \times 10^{22} m^{- 3}$ . What ts n_ein the doped semiconductor?