A quantity of 12 g of magnesium is burnt completely in air ( $O_{2} = 20 %$ and $N_{2} = 80 %,$ by volume). Which of the following is/are correct statement(s) regarding this combustion?

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A minimum of 36 g air is needed if all Mg is converted into MgO only.

A minimum of 6 g air is needed if all Mg is converted into $M g_{3} N_{2}$ only.

A minimum of 40 g air is needed if all Mg is converted into MgO only.

A minimum of 4.67 g air is needed if all Mg is converted into $M g_{3} N_{2}$ only.

answer is A, D.

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Detailed Solution

A) $M g + \frac{1}{2} O_{2} \to M g O$
$\frac{1}{2}$ mole $\frac{1}{4} \times 32 = 8 g$
$∴$ Mass of air needed $= 8 + 1 \times 28 = 36 g$
B) $3 M g + N_{2} \to M g N_{2}$
$\frac{1}{2}$ mole    $\frac{1}{6}$ mole
$∴$ Mass of air needed $= \frac{1}{6} \times 28 + \frac{1}{24} \times 32 = 6 g$