A quantity of electrical charge that brings about the deposition of 4.5 g of Al from A3+ at the cathode will also produce the following volume (STP) of H2(g) from H+ at the cathode

M=E96500XQ4.5=996500XQQ=965002=48250CV of H2=11.2C96500X482500=5.6C

A quantity of electrical charge that brings about the deposition of 4.5 g of Al from A3+ at the cathode will also produce the following volume (STP) of H2(g) from H+ at the cathode

M=E96500XQ4.5=996500XQQ=965002=48250CV of H2=11.2C96500X482500=5.6C

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A quantity of electrical charge that brings about the deposition of 4.5 g of Al from A𝑙³⁺ at the cathode will also produce the following volume (STP) of H₂(g) from H⁺ at the cathode

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44.8L

22.4L

11.2L

5.6L

answer is D.

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Detailed Solution

$M = \frac{E}{96500} XQ$

$4.5 = \frac{9}{96500} XQ$

$Q = \frac{96500}{2} = 48250 C$

$V of H_{2} = \frac{11.2 C}{96500} X 482500 = 5.6 C$

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