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A quantity of gas is collected in a graduated tube over the mercury. The volume of gas at l8°C is 50.0 mL and the level of mercury in the tube is 100 mm above the outside mercury level. The barometer reads 750 torr. Hence, volume at STP is approximately

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40 mL

22 mL

44 mL

20 mL

answer is B.

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Detailed Solution

Under given condition, pressure = 750 - 100 = 650 Torr

$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}, \frac{650 \times 50}{291} = \frac{760 \times V_{2}}{273} ∴ V_{2} = 40 .1 mL$

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