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Q.

A quantity of PCl5 was heated in a 10 litre vessel at 2500C;   PCl5(g)  PCl3(g) + Cl2(g). At equilibrium the vessel contains 0.1 mole of PCl5, 0.20 mole of PCl3 and 0.2 more of Cl2. The equilibrium constant of the reaction is

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a

0.02

b

0.05

c

0.04

d

0.025

answer is C.

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Detailed Solution

KC=PCl3  Cl2PCl5= 0.210 × 0.2100.1/10=0.04

 

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A quantity of PCl5 was heated in a 10 litre vessel at 2500C;   PCl5(g) ⇌ PCl3(g) + Cl2(g). At equilibrium the vessel contains 0.1 mole of PCl5, 0.20 mole of PCl3 and 0.2 more of Cl2. The equilibrium constant of the reaction is