A question paper is split into two parts – part A and part B. Part A contains 5 questions and part B has 4 questions. Each question in part A has an alternative question, student has to attempt at least one question from each part. Find the number of ways in which the student can attempt the question paper

Job 1 : Answering part A

Job 2 : Answering part B

In part A each question can be attempted in 3 ways

1. no question is attempted

2. attempt 1^st part of question

3. attempt 2^nd part of question.

Thus, the total number of ways of answering

Part A $=3^5-1=242$

In part B, each question can be attempted in 2 ways.

$\therefore$ Total number of ways of answering part B $=2^4-1=15$

$\therefore$ Total number of required ways $=242\times 15=3630$.