A radio transmitter radiates 1 kW power at a wavelength 198.6 m. How many photons does it emit per second?

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$10^{10}$

$10^{20}$

$10^{30}$

$10^{40}$

answer is C.

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Detailed Solution

$P = \frac{W}{t} = \frac{nhc}{λt} \Rightarrow 10^{3} = \frac{n \times 6 .6 \times 10^{- 34} \times 3 \times 10^{8}}{198 .6 \times t} \Rightarrow \frac{n}{t} = 10^{30} .$

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