Q.

A radioactive source in the form of a metal sphere of radius 102m emits beta particles (electrons) at the rate of  5  ×  1010  particles per second. The source is electrically insulated. How long will it take ( in  μs) for its potential to be raised by 2 V assuming that 40% of the emitted beta particles escape from the source.(electron charge e=1.6×10-19c   and  14π0=9×109Nm2c-2 )

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answer is 700.

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Detailed Solution

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n=40100×5×1010×t=2×1010×t        q=ne=2×1010×t×1.6×1019   =3.2×109×t

V=RqR2=9×109×3.2×109×t102       t=11440s=700μs

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