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Q.

A railway track runs parallel to a road until a turn brings the road to railway crossing. A cyclist rides along the road every day at a constant speed 20 km/hr. He normally meets a train that travels in same direction at the crossing. One day he was late by 25 minutes and met the train 10 km before the railway crossing. Find the speed of the train.

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a

9 km/hr

b

120 km/hr

c

90 km/hr              

d

40 km/hr

answer is C.

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Detailed Solution

Question Image

tcycle = 10km20 kmh−1 = 12h  = 30 min

Δt= 5 min = 560hr

Train running as per schedule.

So  Vtrain = 10(560) = 10×605 = 120 kmh−1

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