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Q.

A rain drop of radius 0.3 mm falling vertically downwards in air has a terminal velocity of 1 m/s. The viscosity of air is 18 x $10^{- 5}$ poise. The viscous force on the drop is

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a

101.73 $\times 10^{- 5} dyne$

b

$16.95 \times 10^{- 5} dyne$

c

101.73 $\times 10^{- 4} dyne$

d

16.95 $\times 10^{- 4} dyne$

answer is A.

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Detailed Solution

Viscous force = $6 πηrv = 6 πηrv = 6 π \times 18 \times 10^{- 5} \times 0.03 \times 100$

= 101.73 $\times 10^{- 4} dyne$

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