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A random variable X has poisson distribution with mean 2. Then P(x $\geq$ 2) =

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$1 - \frac{3}{e^{2}}$

$\frac{3}{e^{2}}$

$\frac{2}{e^{2}}$

answer is A.

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Detailed Solution

$λ = 2,$ $P (X \geq 2) = 1 - P (X = 0) - P (X = 1) = 1 - e^{- 2} [\frac{2^{0}}{0!} + \frac{2^{1}}{1!}]$

= $1 - e^{- 2} . (3)$

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