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Q.

A random variable x has the following probability distribution: 

X=x012345678
P(X=x)a3a5a7a9a11a13a15a17a

Statement I : The value of 'a' is 181  
Statement II : Mean of random variable X is 6

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a

Statement I and statement II both are true 

b

Statement I is true and Statement II is false

c

Statement I is false and Statement II is true

d

Statement I and statement II both are false 

answer is A.

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Detailed Solution

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ΣP(X=xi)=181a=1   a=181

Mean =μ=ΣxiP(X=xi)=5.48

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