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Q.

A random variable X has the following probability distribution 

X=x01234567
P(X=x)0k2k2k3kk22k27k2+k

Then the mean is

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a

3.26

b

3.33

c

3.66

d

3.17

answer is C.

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Detailed Solution

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Sum of probability = 1

K=1,    110

Mean =366100=3.66

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