Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A random variable X has the probability distribution :

X:12345678P(x):0.150.230.120.100.200.080.070.05

For the events E={X is a prime number} and F=X<4, the probability PEF is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

0.50

b

0.35

c

0.77

d

0.87

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

 E={X is a prime number}=

PE=P2+P3+P5+P7=0.23+0.12+0.20+0.07=0.62

F=X<4

PF=P1+P2+P3=0.15+0.23+0.12=0.5

PEF=P2+P3=0.23+0.12=0.35

PEF=PE+PF-PEF=0.62+0.5-0.35=0.77

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring