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Q.

A random variable X has the probability distribution

X:12345678
p(x):0.150.230.120.100.200.080.070.05

For the events E = { x: x is a prime number} and F={x:x<4}, the probability  P(EF) is

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a

0.35

b

0.77

c

0.87

d

0.50

answer is B.

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Detailed Solution

P(EF)=P(E)+P(F)P(EF)

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