Q.


A ray diagram to represent a convex mirror. On this diagram mark the principal axis, principal focus Question Image and the center of curvature Question Image if the focal length of the convex mirror is Question Image.An object Question Image tall is placed Question Image in front of a convex mirror of focal length Question Image. ____cm is the size of the image formed by the convex mirror.


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Detailed Solution

Concept- 60 cm is the size of image formed. Learn all there is to know about mirrors, including its many components. To determine the location and characteristics of the image, use the mirror formula. The line connecting any mirror's midpoint, primary focus, and curvature center is known as its principal axis.
Formula used:
Mirror's formula is given by, Question Imagewhere, Question Image is the image distance, Question Image is the object distance and Question Image is the focal length of the mirror.
Magnification in a mirror is given by, Question Imagewhere, Question Image is the magnification of the object, Question Image is the image height and Question Image is the object height.
Complete step by step answer:
The marked diagram of a convex mirror with focal length Question Image is given below.
Question ImageIn the figure, Question Image is the principal axis, Question Image is the principal focus and Question Image is the center of curvature.
Here we have given an object of length Question Image and distance of the object from the mirror is,
Question Image focal length of the given convex mirror is Question Image (Since, it is a mirror) . Now, from mirror's formula we have, Question Image where, Question Image is the image distance, Question Image is the object distance and Question Image is the focal length of the mirror.
So, putting the values of object distance Question Image and focal length of the mirror Question Image we have,
Question ImageQuestion ImageSimplifying we have,
Question ImageQuestion ImageQuestion ImageNow, we know magnification in a mirror is given by, Question Image where, Question Image is the image height and Question Image is the object height.
So, putting, object height Question Image object distance Question Image and image distance Question Image we have,
 Question ImageQuestion ImageHence, the image will be Question Image away from the mirror and will be upright, real, and twice as large.
 
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