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A ray emanating from the point $(- 3, 0)$ is incident on the ellipse $16 x^{2} + 25 y^{2} = 400$ at the point P with ordinate 4. Then the equation of the reflected ray is

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3x+4y=16

3x+2y+9=0

4x+3y=12

4x+3y+12=0

answer is B.

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Detailed Solution

$\frac{x^{2}}{25} + \frac{y^{2}}{16} = 1; e = \frac{3}{5} foci (\pm 3, 0); S^{1} (- 3, 0) S (3, 0)$
P(h,4) lies on $\frac{x^{2}}{25} + \frac{y^{2}}{16} = 1 \Rightarrow P (0, 4)$
Required line SP.

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