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Q.

A ray of light enters a spherical drop of a liquid of refractive index  μ=72. This ray after getting reflected from back surface comes out as shown. Given  sin41°=37.

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a

Total deviation suffered by ray (refraction + reflection + refraction) is minimum when  ϕ=60°.

b

Total internal reflection at back surface is not possible for any value of ϕ.

c

Ray suffers total internal reflection at back surface. 

d

When angle of incidence is chosen such that total deviation is minimum, then value of total deviation is 136°.

answer is B, C, D.

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Detailed Solution

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1 sinϕ=72sinr1 and δ=2(ϕ−r1)+π−2r1

δ  is min. when  dδdϕ=0⇒dr1dϕ=12
Since rays enters from air to glass  ⇒   r2≤θc
Thus no TIR from back surface

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A ray of light enters a spherical drop of a liquid of refractive index  μ=72. This ray after getting reflected from back surface comes out as shown. Given  sin41°=37.