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A ray of light enters benzene from the air. The refractive index of benzene is $1.5$ . By what percent, the speed of light reduces on entering the benzene?

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50 %

66.67 %

33.33 %

0 %

answer is C.

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Detailed Solution

The speed of light reduces

33.33 %

on entering the benzene.
Let the speed of light in the air be

c

, and the speed of light in benzene be

v

The formula of refractive index is given as

Refractive index = \frac{Speed of light in air}{Speed of light in benzene}

\Rightarrow

1.5 = \frac{c}{v}

\Rightarrow

v = \frac{c}{1.5}

Percentage decrease in speed of light in benzene

= \frac{c - v}{c} \times 100

= \frac{c - \frac{c}{1.5}}{c} \times 100

= \frac{0.5 c}{1.5 c} \times 100

= 33.33 %

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