Q.

A ray of light falls normally (as shown) on a right angled prism whose  μ=1.5 and 45°. After passing through prism, it falls on a concave mirror which is at a distance of 27.46cm from the point of emergence of prism. The net deviation of the ray is  n×90°, (if focal length of the mirror is 10cm) then value of n is

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Detailed Solution

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BAD=75°       tan75°=BDABBD=2(2+3)=7.46cm

Hence DP = 20 cm i.e., the ray emerging from the prism passes through the centre of curvature of the mirror. 

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