A ray of light falls normally on an equilateral prism of refractive index $μ = \sqrt{3}$ . Match the following table :
i₁ = Angle of incidence
i₂ = Angle of emergence from second surface of prism
r₁ = Angle of refraction at the first surface of prism
r₂ = Angle of incidence at second surface of prism

List-I List-II
(P) Angle i₁ (A) 0°
(Q) Angle r₁ (B) 90°
(R) Angle i₂ (C) 60°
(S) Angle r₂ (D) None
P Q R S
(1) D B A C
(2) B C D A
(3) A B C D
(4) A A D C

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In case of normal incidence , $r_{1} = 0$ and also $i_{1} = 0$

$r_{2} = A - r_{1} = 60^{0} - 0 = 60^{0}$

Now critical angle C = $\sin^{- 1} (\frac{1}{\sqrt{3}}) = 35 . 26^{0}$

Since $r_{2} > C, T I R t a k e s p l a c e a n d h e n c e i_{2} i s m e a n i n g l e s s .$

Watch 3-min video & get full concept clarity