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Q.

A ray of light falls normally on an equilateral prism of refractive index μ=3. Match the following table :
i1 = Angle of incidence
i2 = Angle of emergence from second surface of prism
r1 = Angle of refraction at the first surface of prism
r2 = Angle of incidence at second surface of prism
 

 List-I List-II
(P)Angle i1(A)
(Q)Angle r1(B)90°
(R)Angle i2(C)60°
(S)Angle r2(D)None
 PQRS
(1)DBAC
(2)BCDA
(3)ABCD
(4)AADC

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a

1

b

2

c

3

d

4

answer is D.

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Detailed Solution

In case of normal incidence ,r1 = 0 and also i1 = 0

r2=A-r1=600-0=600

Now critical angle C =sin-113=35.260

Since r2>C , TIR takes place and hence i2 is meaningless.

 

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