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Q.

A ray of light incident at the point (−2,−1) gets reflected from the tangents at (0,−1) to the circle x2+y2=1. The reflected ray touches the circle, the equation of the line along which the incident ray moved is

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a

4x−3y+11=0

b

3x+4y+11=0

c

4x+3y+11=0

d

None of these

answer is B.

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Detailed Solution

Equation of line passing through P is

y+1=m(x+2)  Now r=d⇒m=0,4/3

Question Image

Slope of AB=4/3⇒ Slope of PA=−4/3 slope of incident ray=−4/3 

Incident ray is y+1=−43(x+2)⇒4x+3y+11=0

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