A ray of light incident at the point $(- 2, - 1)$ gets reflected from the tangents at $(0, - 1)$ to the circle $x^{2} + y^{2} = 1 .$ The reflected ray touches the circle, the equation of the line along which the incident ray moved is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$4 x - 3 y + 11 = 0$

$3 x + 4 y + 11 = 0$

$4 x + 3 y + 11 = 0$

None of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Equation of line passing through P is

$y + 1 = m (x + 2) Now r = d \Rightarrow m = 0, 4 / 3$

Slope of $AB = 4 / 3 \Rightarrow Slope of PA = - 4 / 3 slope of incident ray = - 4 / 3$

Incident ray is $y + 1 = - \frac{4}{3} (x + 2) \Rightarrow 4 x + 3 y + 11 = 0$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE