A ray of light incident at the point $(- 2, - 1)$ gets reflected from the tangents at $(0, - 1)$ to the circle $x^{2} + y^{2} = 1 .$ The reflected ray touches the circle, the equation of the line along which the incident ray moved is

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$4 x - 3 y + 11 = 0$

$3 x + 4 y + 11 = 0$

$4 x + 3 y + 11 = 0$

None of these

answer is B.

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Detailed Solution

Equation of line passing through P is

$y + 1 = m (x + 2) Now r = d \Rightarrow m = 0, 4 / 3$

Slope of $AB = 4 / 3 \Rightarrow Slope of PA = - 4 / 3 slope of incident ray = - 4 / 3$

Incident ray is $y + 1 = - \frac{4}{3} (x + 2) \Rightarrow 4 x + 3 y + 11 = 0$

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