A ray of light is incident normally on one of the faces of a prism of apex angle 30∘ and refractive index 2 . The angle of deviation of the ray is …… degrees.

For side AC, Snell's law gives,μsinr2=1×sine ⇒2sin30o=sine ⇒e=45oDeviation = δ=i+e-A=0+45°-30°=15°

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A ray of light is incident normally on one of the faces of a prism of apex angle $30^{\circ}$ and refractive index $\sqrt{2}$ . The angle of deviation of the ray is …… degrees.

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answer is 15.

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For side AC, Snell's law gives,

${μsinr}_{2} = 1 \times sine \Rightarrow \sqrt{2} \sin 30^{o} = sine \Rightarrow e = 45^{o}$

Deviation = $δ = i + e - A = 0 + 45 ° - 30 ° = 15 °$

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