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Q.

A ray of light is incident on an equilateral prism in such a way that the angle of incidence is equal to the angle of emergence and each is equal to 3/4 of the prism angle. The angle of deviation for the ray of light is

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a

$45^{0}$

b

$20^{0}$

c

$39^{0}$

d

$30^{0}$

answer is B.

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Detailed Solution

$A = 60^{0}$

$i_{1} = i_{2} = i = \frac{3}{4} \times 60^{0} = 45^{0}$

$d = (i_{1} + i_{2}) - A$

$= 90 - A = 30^{0}$

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