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A ray of light of wavelength 500 nm falls at glancing angle of 37⁰ on a transparent slab from air so that reflected and refracted rays are mutually perpendicular. The ratio of wavelength of reflected and refracted rays is

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Detailed Solution

If reflected and refracted rays are perpendicular i+r=90⁰

r=90⁰-i

$i = 53^{0}, r = 37^{0}$

$μ_{1} \sin 53 = μ_{2} \sin 37$

$\frac{μ_{1}}{μ_{2}} = \frac{3}{4}$

$μ \propto \frac{1}{λ}$

$\frac{λ_{1}}{λ_{2}} = \frac{4}{3}$

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