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Q.

A ray of light passes normally through a slab $μ$ = 1.5 of thickness 't'. If the speed of light in vacuum be 'C', then time taken by the ray to go across the slab will be

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a

$\frac{4 t}{9 C}$

b

$\frac{t}{C}$

c

$\frac{3 t}{2 C}$

d

$\frac{2 t}{3 C}$

answer is B.

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Detailed Solution

Speed of light in the material = $v = \frac{C}{μ}$

Time taken to travel in the slab $= \frac{t}{v} = \frac{μ t}{C} = \frac{3 t}{2 C}$

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