Q.

A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 shown in the figure. If the angle of incidence of ray is  θ,the value of  θ is

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a

sin1(1318)

b

sin1(1316)

c

sin1(89)

d

sin1(813)

answer is C.

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Detailed Solution

μrμd=μ3μ2=sinc;

μ2μ1=sinθsinc 

μ1sinθ=μ2sinc=μ3sin90

1.6sinθ=1.8sinc=1.3

sinθ=1316

θ=sin11316

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