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Q.

A ray of light suffers refraction at the air glass interface of a parallel faced slab of thickness 10 cm. The angle of incidence and refraction are $60 °$ and $30 °$ respectively. The lateral shift of the light ray is

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a

\frac{5}{\sqrt{2}} cm

b

\frac{10}{\sqrt{3}} cm

c

\frac{10}{\sqrt{2}} cm

d

\frac{5}{\sqrt{3}} cm

answer is A.

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Detailed Solution

L i = 60 °

$Lr = 30 °$

$t = 10 cm$

Later shift $= t . \frac{\sin (i - r)}{\cos r}$

$= 10. \frac{\sin (30)}{\cos 30}$

$= 10. \tan 30$

$= 10 \times \frac{1}{\sqrt{3}} = \frac{10}{\sqrt{3}} cm$

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