Q.

A ray of light travelling in air is incident at angle of incidence I ≈ 90° on a long rectangular slab of a transparent medium of thickness y0. The medium has a variable refractive index of μ(x)=1+e2x/a;x0, where ‘a’ is a positive constant. If the value of y0 = a/2, then

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a

the co-ordinates of the point where the ray intersects the upper surface of the slab-air boundary are a2ln2,a2

b

the angle made by light ray with +ve x-axis, at the upper surface of slab air boundary, inside the medium is tan112

c

the angle made by light ray with +ve x-axis, at the upper surface of slab air boundary, inside the medium is π/3

d

the co-ordinates of the point where the ray intersects the upper surface of the slab-air boundary are aln2,a2

answer is A, D.

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Detailed Solution

Sinθ=1μ=1e2x/a+1

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tanθ=1e2x/a  ........ (1)

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Again, slope of the tangent

tanθ=dydx ........ (2)

from 1 & 2,

dydx=1e2x/a

0ydy=0xdxe2x/a

y=0xdxex/a

y=exa0x[a]=a1ex/a

at y=a2,

a2=a1ex/a

ex/a=12

ex/a=2x=aln2

At the upper surface of the boundary, ex/a=2

μ=1+e2x/aμ=1+ex/a2=5

at the surface, Sin90o=μSinθ=5Sinθ

Sinθ=15tanθ=12

θ=tan112

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