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A ray of light travels in the way as shown in the fig. After passing through water, the ray grazes along the water air interface. The value of $μ_{g}$ in terms of ‘i’ is $(μ_{w} = 4 / 3)$

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$\frac{1}{\sin i}$

$\frac{3}{4 \sin i}$

$\frac{4}{3 \sin i}$

$\sin i$

answer is A.

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Detailed Solution

$μ_{1} \sin i_{1} = μ_{2} \sin i_{2}$

$μ_{1} = μ_{w}; i_{1} = i; μ_{2} = μ_{a} = 1$

$i_{2} = 90^{0}$

For the water air interface

$μ_{w} \sin i = (1) \sin 90^{0}$

For the medium - water interface

$μ_{g} \sin i = μ_{g} \sin i_{1} = (1) \sin 90^{0}$

$μ_{g} = \frac{1}{\sin i}$

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