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A ray of monochromatic light is incident on an interface separating two media, making an angle $θ_{1}$ with the interface and the refracted ray makes an angle of $θ_{2}$ with the interface. If $C_{1}$ and $C_{2}$ are the speed of light in the two media respectively, which of the following is correct law of refraction?

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$\frac{{sinθ}_{1}}{C_{2}} = \frac{{sinθ}_{2}}{C_{1}}$

$\frac{\sin θ_{1}}{C_{1}} = \frac{\sin θ_{2}}{C_{2}}$

$\frac{{cosθ}_{1}}{C_{1}} = \frac{{cosθ}_{2}}{C_{2}}$

$\frac{{cosθ}_{1}}{C_{2}} = \frac{{cosθ}_{2}}{C_{1}}$

answer is D.

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Detailed Solution

Angle of incidence in first medium = $90^{0} - θ_{1}$ and angle of refraction in the second medium $= 90^{0} - θ_{2}$ . Apply the usual law of refraction $μ_{1} \sin i_{1} = μ_{2} \sin i_{2}$ and use $μ = c_{0} / c$

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