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A reaction follows the rate law, $R = K [A]^{m} [B]^{n}$ . From the following information, calculate the value of m and n
[Al [B] $t_{1 / 2}$
1 $2 \times 10^{- 3} M$ 4M 20 min
2 $4 \times 10^{- 3} M$ 4M 40 min
3 $2 \times 10^{- 3} M$ 8M 20min

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An Intiative by Sri Chaitanya

m = 0, n = 0

m = 1, n = l

m = 1, n = 0

m = 0, n = 1

answer is B.

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Detailed Solution

$t_{1} = \frac{62 π}{10}$

$20 = k = k {[2 \times 10^{- 3}]}^{k n} [4]^{h}$

$40 = k = k {[4 \times 10^{- 3}]}^{h} [4]^{n}$

$2 = {[\frac{4 \times 10^{- 3}}{2 \times 10^{3}}]}^{n_{3}}$ , $n = 0$

$2 = (2)^{m}$ = $m = 1$

$m = 1, n = 0$

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