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Q.

A reaction is carried out at 600 K. If the same reaction is carried out in the presence of catalyst at the same rate and same frequency factor, the temperature required is 500 K. What is the activation energy of the reaction, if the catalyst lowers the activation energy barrier by 20 kJ/ mol ?

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a

120 kj/mol

b

100 kj/mol

c

80

d

None of these

answer is B.

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Detailed Solution

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$K = {Ae}^{- E_{a} / RT} In absence of catalyst, K_{1} = {Ae}^{- E_{a} / R \times 600} In presence of catalyst, K_{2} = {Ae}^{- (E_{a} - 20) / R \times 500} K_{1} = K_{2} \frac{E_{a}}{R \times 600} = \frac{(E_{a} - 20)}{R \times 500} \frac{E_{a}}{6} = \frac{(E_{a} - 20)}{5} E_{a} = 120 Kj / mol$

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