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A reaction was found to be of second order with respect to the concentration of carbon monoxide. If the concentration of carbon monoxide is doubled with everything else kept the same, the rate of the reaction will :

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remain unchanged;

be tripled;

increase by a factor of 4;

be doubled

answer is C.

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Detailed Solution

Since the reaction is of second order, we have:
$Rate = \frac{dx}{dt} = k [CO]^{2} .$
Hence, according to rate law expression, doubling the concentration of $CO$ increases the rate by a factor of 4.

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