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A reaction which is of first order w.r.t . reactant A, has a rate constant $6 \min^{- 1}$ . If we start with
$[A] = 0.5 m o l L^{- 1},$ when would [A] reach the value of 0.05 mol $L^{- 1}$

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An Intiative by Sri Chaitanya

0.15 min

3 min

0.384 min

3.84 min

answer is A.

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Detailed Solution

$t = \frac{2.303}{k} \log \frac{a}{a - x} = \frac{2.303}{6} \log \frac{0.5}{0.05} = 0.384 \min$

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