Q.

A reaction AB is of the order 2.5 with respect to A. The half-life of the reaction will be given 

Moderate

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a

0.693/k

b

1/[A]0k

c

k/[A]0

d

1/1.5k[A]01.521.51

answer is D.

(Detailed Solution Below)

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Detailed Solution

d[A]dt=k[A]2.5. 

Hence, d[A][A]2.5=kdt. 

Thus

 1[A]1.51[A]01.5=(1.5)kt 

For  t0.5, [A]=[A]0/2  

Hence 

 1[A]0/21.51[A]01.5=1.5kt0.5t0.5=11.5k[A]01.521.51

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