A reaction $N_{2} + 3 H_{2} ⇌ 2 N H 3_{} + 92 k J$ is at equilibrium. If the concentration of $N_{2}$ is increased the temperature of the system

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increases

remains constant

decreases

becomes half

answer is B.

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Detailed Solution

The reaction, $N_{2} + 3 H_{2} ⇌ 2 N {H_{3}}_{} + 92 k J$ , Ammonia production is an exothermic process. The reaction shifts backward when the temperature rises in order to cancel out the effect of the rise in temperature.

Therefore, the correct answer is option B increases.

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