'A' reacts with C2H5I giving 'B' and Nal. Here 'A' and 'B' respectively are

It is an important laboratory method for the preparation of symmetrical and unsymmetrical ethers. In this method, an alkyl halide is allowed to react with sodium alkoxide.C2H5I+C2H5O-Na+A→C2H5-O-C2H5B+NaI

'A' reacts with C2H5I giving 'B' and Nal. Here 'A' and 'B' respectively are

It is an important laboratory method for the preparation of symmetrical and unsymmetrical ethers. In this method, an alkyl halide is allowed to react with sodium alkoxide.C2H5I+C2H5O-Na+A→C2H5-O-C2H5B+NaI

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'A' reacts with C₂H₅I giving 'B' and Nal. Here 'A' and 'B' respectively are

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$C_{2} H_{5} OH, C_{2} H_{5} {OC}_{2} H_{5}$

$C_{2} H_{5} ONa, C_{2} H_{5} {OC}_{2} H_{5}$

${CH}_{3} COONa, {CH}_{3} {OCH}_{3}$

$C_{2} H_{5} {OC}_{2} H_{5}, C_{2} H_{5} {COOC}_{2} H_{5}$

answer is C.

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Detailed Solution

It is an important laboratory method for the preparation of symmetrical and unsymmetrical ethers.
In this method, an alkyl halide is allowed to react with sodium alkoxide. $C_{2} H_{5} I + \underset{A}{C_{2} H_{5} O^{-} {Na}^{+}} \to \underset{B}{C_{2} H_{5} - O - C_{2} H_{5}} + NaI$