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A real gas is subjected to an adiabatic process from (2 bar, 40 L, 300 K) to (4 bar, 30 L, 300 K) against a constant pressure of 4 bar. The enthalpy change for the process is (1 bar - litre = 100 J):

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zero

10000 J

8000 J

6000 J

answer is C.

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Detailed Solution

$\begin{array}{l} q = 0; Δ U = - 4 (30 - 40) = + 40 \\ Δ H = Δ U + Δ (P V) = 40 + (120 - 80) = 80 L - bar \\ Δ H = 8000 J \end{array}$

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